- $$\frac{{1}}{{6}}$$
- $$\frac{{2}}{{3}}$$
- $$\frac{{4}}{{9}}$$
- $$\frac{{5}}{{6}}$$
Answer: Option 1
In a simultaneous throw of two dice, we have n(s) = 6 × 6 = 36 Let E = event of getting two numbers are same. Then E = {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)} therefore, n(E) = 6 And p(E) = p(getting two numbers are same) $$\eqalign{ & {\text{p}}\left( {\text{E}} \right) = \frac{{{\text{n}}\left( {\text{E}} \right)}}{{{\text{n}}\left( {\text{S}} \right)}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{6}{{36}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \frac{1}{6} \cr} $$ Hence the answer is $$\frac{{1}}{{6}}$$