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Answer: Option 2

Let the capacity of the tank be 100 litres. Then, Initially : A type petrol = 100 litres After first operation : A type petrol = $$\left( {\frac{{100}}{{2}}} \right)$$ = 50 litres ; B type petrol = 50 litres After second operation : A type petrol = $$\left( {\frac{{50}}{2} + 50} \right)$$  = 75 litres ; B type petrol = $$\left( {\frac{{50}}{2}} \right)$$ = 25 litres After third operation : A type petrol = $$\left( {\frac{{75}}{2}} \right)$$ = 37.5 litres B type petrol = $$\left( {\frac{{25}}{2} + 50} \right)$$  = 62.5 litres ∴ Required percentage = 37.5%

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