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(z-1)(z+2)=(z+4)(z-2) সমাধান করে পাই,x=6

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(z-1)(z+2)=(z+4)(z-2) => z^2+2z-z-2=z^2-2z+4z-8 => z^2+2z-z-2-z^2+2z-4z+8=0 => 4z-4z-z+6=0 =>6=z =>z=6 (ans.)

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